我在此一栏有数据。
Test 20019-2000 test
Test 119 test
Test 19-EM
Test EM - 19
缩略语 但是,我的要求是,它应该把象征性的扼杀从“19”开始的row起。
它只应指第3和第4行。 请就此帮助我。
提前感谢。
Oracle regexp does not support the traditional word boundry operators or <. But you can simulate this by matching the start of string OR a non-word character immediately before the 19.
E.g. 我在此将一字界定为字母数字序列。 因此,你需要
REGEXP_LIKE( mesage, (A|W)19 )
fred 19,fred.19,但fred19/code>。 如果你确实想把一字定义为非白色空间,因此与<条码>fred.19<>/code>不一致。 改动
REGEXP_LIKE( mesage, (A|s)19 )
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