Question

我有2个管道有限档案。昨天和今天。 txt

昨天txt:

1234|12|Bill|Blatt|programmer
3243|34|Bill|Blatt|dentist
98734|25|Jack|Blatt|programmer
748567|31|Mark|Spark|magician

今天,txt

123|12|Bill|Blatt|programmer
3243|4|Bill|Blatt|dentist
934|25|Jack|Blatt|prograbber
30495|89|Dave|Scratt|slobber

I would like to compare the 2 files while ignoring the first 2 fields and output any lines unique to the second file (今天,txt), but I want the full lines even though the comparison is omitting the first 2 fields. So in the case above the output would be:

new_今天,txt

934|25|Jack|Blatt|prograbber
30495|89|Dave|Scratt|slobber

我试图利用这一点:

sort <(cut -d"|" -f3- yesterday.txt) <(cut -d"|" -f3- yesterday.txt) <(cut -d"|" -f3- 今天,txt) | uniq -u

这几乎是行之有效的,但它给我留下了我削减的2个领域。我不知道如何做到这一点。任何帮助都会受到高度赞赏。

Answer 1

Reusing most of your code:

sort <(cut -d"|" -f3- yesterday.txt) 
     <(cut -d"|" -f3- today.txt) |
     uniq -u |
     xargs -I% grep  %  today.txt || true

Output

30495|89|Dave|Scratt|slobber
934|25|Jack|Blatt|prograbber

Answer 2

。不能轻易地忽视管道有限的田地,否则会理想。借助空间有限投入,你才能做到:

sort -k3 yesterday.txt yesterday.txt today.txt |
uniq -f2 -u

如果我们在运行<条码>uniq<<><>条码>之前抽取空间和管道,然后在其后回击:

sort -t |  -k3 yesterday.txt yesterday.txt today.txt |
tr   |   |   |
uniq -f2 -u |
tr   |   |

Reusing most of your code:

Output

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