Question

I have an array:

> a

array([[1, 2, 3], [2, 3, 4], [3, 4, 5]])

我想把这些价值观改变为这些价值观的瓦解,因此产出将是:

> a

array([[2, 2, 2], [3, 3, 3], [4, 4, 4]])

如果不使用<<>条码/条码>,是否可迅速做到这一点?

Answer 1

a.mean(axis=1) gets the row mean and np.broadcast_to broadcasts the result to the desired shape. .T just returns transpose of the result

import numpy as np
a = np.array([[1, 2, 3], [2, 3, 4], [3, 4, 5]])
np.broadcast_to(a.mean(axis=1), a.shape).T

产出:

array([[2., 2., 2.],
       [3., 3., 3.],
       [4., 4., 4.]])

Answer 2

页: 1 如果不使用<<>条码/条码>,是否可迅速做到这一点? ......

You can use a list comprehension.
Note, I m using the int function here, since your provided data was non-fractional.

a = [[1, 2, 3], [2, 3, 4], [3, 4, 5]]
a = [([int(sum(x) / len(x))] * 3) for x in a]

Output

[[2, 2, 2], [3, 3, 3], [4, 4, 4]]