Question

In cython the marshalling of the types like int or char is done automatically, but if I use a

       cdef struct MyClass_Tag:
            pass
      ctypedef MyClass_Tag* MyClass_ptr
      ....
      cdef class MyClass:
           cdef MyClass_ptr obj
           ....

Now for wrapping any function like for example in c is some function foo that takes

      foo(char* , MyClass_ptr self)
           #return stuff

总结这一职能:

       def py_foo(char* n, self):
            return foo(n,self.obj)

So from py to c:

       char is done automatically
       but self is of type MyClass so to call the foo i have to write self.obj , 
       so i pass the same obj

这里发生的情况是,从y到 c。

The problem is that I don t understand where happen the marshalling from c to py, I mean at which point does it happen?

Even in this case or even if you give me some other example it will be ok. Thank you!

Answer 1

我没有完全理解你的问题,但你可能要利用指挥:

cython -a <yourfile.pyx>

然后,用你的网络浏览器开张。你们看一看cy如何将你的法典翻译成C,然后找到你的答复:

Answer 2

作为参数名称<代码>本身建议Cfoo()功能作为在沙捞中的一种方法具有更大的意义:

cdef extern void c_foo "foo" (char* n, MyClass_ptr)

cdef class MyClass:
   cdef MyClass_ptr this

   def foo(self, unicode n not None):
       b = n.encode( ascii )
       cdef char* p = b
       c_foo(p, self.this)

另见。 C Library。

Cython将你的代码翻译成C(或C++)。此时此刻,你可以忘记这一点。根特的C法典是一种普通的C推广法,适用于沙尔。该守则载有普通的“快速通道”:PyBytes_AsString(>。 (convertshed bytes to char* or PyInt_FromLong ( (convert C int to Zhu integer).

<编码> MyClass_ptr a. 使用:

struct __pyx_obj_3foo_MyClass {
  PyObject_HEAD
  MyClass_ptr this; /* <-- using MyClass_ptr as is */
};

i. 即,纯粹的沙尔法从来就看不见它,因此没有从/转成灰色物体。

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