Question

Suppose I write a basic PromQL query like this

Query: kube_deployment_spec_replicas{}

Result: kube_deployment_spec_replicas{deployment="mydeployment",endpoint="myendpoint",instance="myinstance",job="myjob",namespace="default",pod="mypod",service="myservice"}

Is there a clean way to omit instance and pod from the resulted timeseries?

Desired: kube_deployment_spec_replicas{deployment="mydeployment",endpoint="myendpoint",job="myjob",namespace="default",service="myservice"}

Answer 1

Try using something like the following as Sergio already suggested:

sum(kube_deployment_spec_replicas) without (instance, pod)

This query will remove instance and pod labels from the result. Note that the query won t work as expected if there are multiple kube_deployment_spec_replicas time series with identical (instance, pod) set of labels. In this case the query will sum up these time series.

p.s. MetricsQL - PromQL-like query language from Prometheus-like monitoring system - VictoriaMetrics - provides more obvious solution to delete labels with label_del function:

label_del(kube_deployment_spec_replicas, "instance", "pod")

Disclosure: I m the author of VictoriaMetrics.

Answer 2

You need to use Prometheus query operators. You can use avg or sum depending on your use case.

You can check here for more information: here

Answer 3

Try sum by (labelName), eg:

sum by (job) (
  rate(http_requests_total[5m])
)

This will aggregate all http_requests_total metric by its job label.

Doc: https://prometheus.io/docs/prometheus/latest/querying/examples/#:~:text=we%20might%20want%20to%20sum%20over%20the%20rate%20of%20all%20instances

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