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Monte Carlo and Area -calculation
原标题:Monte Carlo and Area -calculation

接近0.3

$ cat monte.py 
import random,math
density=int(1e6)
x = [random.uniform(0,1)*7*math.pi for _ in range(density)]
y = [random.uniform(0,1) for _ in range(density)]
i = [math.sin(xx)*math.cos(xx) > yy for (xx,yy) in zip(x,y)]

print sum(i)/(float(density)*10.0)*7*math.pi

$ python monte.py 
0.350184850795

我正试图改写如下,但出于某种原因, code法甚至没有结束。

x = rand(1, 1000000)*7pi;
y = rand(1, 1000000);
i = sin(x).* cos(x) >y;
Area3 = (sum(i) / 10000000)*7pi;
最佳回答

I m 在您的书目和书本之间取得相同结果...... 您是否确信,配对版正给你们2,而不是0.35?

例如:

MATLAB:

x = rand(1, 1000000)*7*pi;
y = rand(1, 1000000);
i = sin(x).* cos(x) >y;
Area3 = (sum(i) / 10000000)*7*pi

该数值:0.3511

页: 1

import random,math
density=int(1e6)
x = [random.uniform(0,1)*7*math.pi for _ in range(density)]
y = [random.uniform(0,1) for _ in range(density)]
i = [math.sin(xx)*math.cos(xx) > yy for (xx,yy) in zip(x,y)]

print sum(i)/(float(density)*10.0)*7*math.pi

这一结果:0.347935156296

假设:

import numpy as np
x = np.random.random(1e6) * 7 * np.pi
y = np.random.random(x.size)
i = np.sin(x) * np.cos(x) > y
print 7 * np.pi * i.sum() / (10 * x.size)

该数值:0.350475133957

问题回答

暂无回答




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