Question

例:

number1 = 54378
number2 = 54379
if number1 (is similar to) number2:
   print (number1 + " " + number2)
   input("what to do")

我想比较这两个数字,如果出现这种(在1和2号之间)相似之处,则让方案通知我。

我希望,解决办法具有灵活性,具有一些更相似之处(第一位数不同)。

BTW,我正在使用3.X。

Answer 1

http://docs.python.org/library/difflib.html”。

>>> from difflib import SequenceMatcher
>>> number1 = 54378
>>> number2 = 54379
>>> SequenceMatcher(None, str(number1), str(number2)).ratio()
0.80000000000000004

在建立<条码>后 http://docs.python.org/library/difflib.html#difflib.SequenceMatcher.ratio"rel=“nofollow”ratio((或quick_ratio(>>>或real_quick_ratio(),如果速度有问题的话,可在0到1之间获得类似评级。

在玩之后,你可以指出,什么是好衡量标准,说明它们应当如何相近,并像这样使用:

metric = 0.6   # just an example value
if SequenceMatcher(None, str(a), str(b)).ratio() > metric:
    # a and b are similar

Answer 2

you could do one of the following:
Both will take in uneven numbers such as (100, 10) (200, 12)

from itertools import izip_longest
def findSim(a, b):
    aS = str(a)
    bS = str(b)

    return [abs(int(x)-int(y)) if y != None else int(x) for x,y in izip_longest(aS,bS)]

一份列有所有立场差异的清单,

from itertools import izip_longest
def findSim(a, b):
    aS = str(a)
    bS = str(b)

    return sum(abs(int(x)-int(y)) if y != None else int(x) for x,y in izip_longest(aS,bS))

returns the sum difference of all positions.

友情链接