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R[复制品]的心脏
原标题:Plot a heart in R [duplicate]
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Closed 11 years ago.

Possible Duplicate:
Equation-driven smoothly shaded concentric shapes

我怎么能够把像我所策划的圈子(使用地块)或 rec子一样的不对称心脏划一?

我也这样说,以便我实际上能够这样做,并且能够把这一点与今后类似的需要结合起来。 我看到了比这更细致的地块,因此,那是站不住脚的。

最佳回答

这是划出“对称方程式”的一个实例,即对具有共同参数的x和 y两种不同方程式进行配对。 你们可以找到许多共同的 cur子和形状,可以在这种框架内书写。

dat<- data.frame(t=seq(0, 2*pi, by=0.1) )
 xhrt <- function(t) 16*sin(t)^3
 yhrt <- function(t) 13*cos(t)-5*cos(2*t)-2*cos(3*t)-cos(4*t)
 dat$y=yhrt(dat$t)
 dat$x=xhrt(dat$t)
 with(dat, plot(x,y, type="l"))

rel=“noreferer”> 其他参数(含蓄和极性)

You also could "heat it up" with using the "fill" capability of the polygon function:

with(dat, polygon(x,y, col="hotpink"))   

如果你只想在不同地点周围进行点火,那么,在阅读<条码>帮助(点)页和使用<条码>后,你可以使用“轮式”:

points(c(10,-10, -15, 15), c(-10, -10, 10, 10), pch=169, font=5)

“entergraph

Windows users may want to see if adding the Cairo package helps gain access to card symbols including "hearts".( When I tested the TestChars function on the WinXP "side" of my MacPro I did not get hearts, and paging through the "special symbols" in MS-Word did not uncover anything. So I did a search of Rhelp and found a recent posting by Ivo Welch. He was reporting a bug, but they look OK on my machine.) Further note... I think the hearts and diamonds codes in his were reversed.

library(Cairo)

clubs <- expression(symbol( 247 ))
hearts <- expression(symbol( 251 ))
diamonds <- expression(symbol( 250 ))
spades <- expression(symbol( 252 ))
csymbols <- c(clubs, hearts, diamonds, spades)

plot( 0, xlim=c(0,5), ylim=c(0,2), type="n" )
clr <- c("black", "red", "red", "black") 
for (i in 1:4) {
  hline <- function( yloc, ... ) 
         for (i in 1:length(yloc)) 
             lines( c(-1,6), c(yloc[i],yloc[i]), col="gray")  
              hline(0.9); 
                hline(1.0);
                hline(1.1);
                hline(1.2)  
 text( i, 1, csymbols[i], col=clr[i], cex=5 )  
 text( i, 0.5, csymbols[i], col=clr[i] ) }

# Also try this
plot(1,1)
text(x=1+0.2*cos(seq(0, 2*pi, by=.5)), 
     y=1+0.2*sin(seq(0, 2*pi, by=.5)), 
                  expression(symbol( 251 ) ) )

enter image description here

问题回答

rel=“noreferer” 从博客中选取

解决对等的参数(允许采用数学格式吗?)

x^2 +(5y/4-sqrt(abs(x))^2 = 1

sqrt(1-x^2) = 5y/4 - sqrt(abs(x))

y = 4/5*(sqrt(1-x^2)+sqrt(abs(x))

MASS::eqscplot(0:1,0:1,type="n",xlim=c(-1,1),ylim=c(-0.8,1.5))
curve(4/5*sqrt(1-x^2)+sqrt(abs(x)),from=-1,to=1,add=TRUE,col=2)
curve(4/5*-sqrt(1-x^2)+sqrt(abs(x)),from=-1,to=1,add=TRUE,col=2)

enter image description here

简单易 ha:

plot(1, 1, pch = "♥", cex = 20, xlab = "", ylab = "", col = "firebrick3")

此处为<代码>ggplot的心脏病:

library(ggplot2)

dat <- data.frame(x=seq(0, 2*pi, length.out=100))
cardioid <- function(x, a=1)a*(1-cos(x))
ggplot(dat, aes(x=x)) + stat_function(fun=cardioid) + coord_polar()

“enterography

And the heart plot (linked by @BenBolker):

heart <- function(x)2-2*sin(x) + sin(x)*(sqrt(abs(cos(x))))/(sin(x)+1.4)
ggplot(dat, aes(x=x)) + stat_function(fun=heart) + coord_polar(start=-pi/2)

“entergraph

Another option,

xmin <- -5
xmax <- 10
n <- 1e3
xs<-seq(xmin,xmax,length=n)
ys<-seq(xmin,xmax,length=n)

f = function(x, y) (x^2+0.7*y^2-1)^3 - x^2*y^3
zs <- outer(xs,ys,FUN=f)

h <- contourLines(xs,ys,zs,levels=0)
library(txtplot)
with(h[[1]], txtplot(x, y))



     +---+-******----+----******-+---+
 1.5 + *****    **********     ***** +
   1 +**                           * +
 0.5 +**                           * +
     | ***                       *** |
   0 +   ****                 ****   +
-0.5 +      *****         *****      +
  -1 +          ***********          +
     +---+-----+-----*-----+-----+---+
        -1   -0.5    0    0.5    1    

如果你想成为更多的“成熟”,就会尝试以下几个方面(几年前给帮助):

thong<-function(h = 9){ 
     # set up plot  
    xrange=c(-15,15)  
    yrange=c(0,16)  
    plot(0,xlim=xrange,ylim=yrange,type= n )  

     # draw outer envelope  
    yr=seq(yrange[1],yrange[2],len=50)  
    offsetFn=function(y){2*sin(0+y/3)}  
    offset=offsetFn(yr)  
    leftE = function(y){-10-offsetFn(y)}  
    rightE = function(y){10+offsetFn(y)}  

    xp=c(leftE(yr),rev(rightE(yr))) 
    yp=c(yr,rev(yr))  
    polygon(xp,yp,col="#ffeecc",border=NA) 

    # feasible region upper limit: 
    # left and right defined by triple-log function:  
    xt=seq(0,rightE(h),len=100)   
    yt=log(1+log(1+log(xt+1)))   
    yt=yt-min(yt)  
    yt=h*yt/max(yt)  
    x=c(leftE(h),rightE(h),rev(xt),-xt) 
    y=c(h,h,rev(yt),yt) 
    polygon(x,y,col="red",border=NA)  
}

A few more varieties:

“equations”/

我不了解有关R的任何情况,但如果你策划这项职能,你将心中:

x^2+(y-(x^2)^(1/3))^2=1




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