“Django”项目文档中包含以下两条内容:
BASE_DIR = os.path.dirname(os.path.dirname(os.path.abspath(__file__)))
PROJECT_ROOT = os.path.dirname(os.path.abspath(__file__))
我想知道这一区别,因为我认为两者都提到同一目录。 如果你能够提供某些链接,也会大有助益。
“Django”项目文档中包含以下两条内容:
BASE_DIR = os.path.dirname(os.path.dirname(os.path.abspath(__file__)))
PROJECT_ROOT = os.path.dirname(os.path.abspath(__file__))
我想知道这一区别,因为我认为两者都提到同一目录。 如果你能够提供某些链接,也会大有助益。
PROJECT_ROOT = os.path.dirname(os.path.abspath(__file__))
BASE_DIR = os.path.dirname(PROJECT_ROOT)
由于,os.path.dirname(
Function简单地排除了一条道路的最后一段。
见上文<代码>_file_。 现有模块的名称,见
http://www.un.org/Depts/DGACM/index_french.htm 然而,它可以是relative path,这样,>
附录一
my_new_app
|
└───my_new_app
│ │
│ │ settings.py
│ │ ...
| manage.py
然后,os.path.abspath(__file__)
回到绝对的道路上来dings.py
file,
os.path.dirname(os.path.abspath(__file__))
返回内联网的路程my_new_app
rafter and path.dirname(os.path.dirname (os.path.spth.abath(file__file__))code/code 返回外联网
在最近版本的Django(例如,第4.2.5版)中,而不是os
,pathlib
。 模块使用,因此对应结构是:
from pathlib import Path
BASE_DIR = Path(__file__).resolve().parent.parent
PROJECT_ROOT = Path(__file__).resolve().parent
There s a special case where if settings.py
is already in the root directory on your environment (e.g. the C drive on a local machine) so that its path looks like C:settings.py
, then BASE_DIR == PROJECT_ROOT
may be True. This is probably not how it should be, so if BASE_DIR and PROJECT_ROOT are the same, then you probably need to re-structure your project.
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