Question

我有以下法典:

jobsToShiftUp.AddRange(PresentationManager.Instance.ScheduleViewSource.Where(o => o.Resources.First().ResourceName == criticalJob.Resources.First().ResourceName && ((o.Start >= criticalJob.Start) || (o.Start < criticalJob.Start && o.End > criticalJob.Start)) && !o.JobGuid.Equals(((Job)state.DraggedAppointments.First()).JobGuid) && GetWeekNumber(o.Start) == GetWeekNumber(criticalJob.Start)));
jobsToShiftUp = jobsToShiftUp.OrderBy(o => o.Start).ToList();
TimeSpan timeToShift = criticalJob.End - jobsToShiftUp.First().Start;

foreach (Job job in jobsToShiftUp)
{
    if (jobsToShiftUp.IndexOf(job) == 0)
    {
        ((ObservableCollection<Job>)state.DestinationAppointmentsSource).Single(o => o.JobGuid.Equals(job.JobGuid)).Start += timeToShift;
        ((ObservableCollection<Job>)state.DestinationAppointmentsSource).Single(o => o.JobGuid.Equals(job.JobGuid)).End += timeToShift;

......

最后一个两条线(增加就业机会的开始和结束性质)既影响到国家,也影响到目的地名单和工作机会。清单(即,它影响到目前在每个路口中提到的工作对象)。我想,它为什么会影响到ToShiftUp就业名单!

Answer 1

I think both object have same reference.

So jobs ToShiftUp Collection and state.DestinationAppointments 资料来源:可能都有相同的参考文献,并更新了另一个参考文献。



您可使用克隆技术(制版)来避免这种情况。

Answer 2

Since both list contain the same instances of objects. Like:

Job job = new Job();
List<Job> list1 = new List<Job>{job};
List<Job> list2 = new List<Job>{job};

list [0]. 起始+=10

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