例如:2.44444
。 我需要先到点数——就我而言是<条码>4条码>。 如何执行?
For example, let s say I want to find a particular word or number in a file. The contents are in sorted order (obviously). Since I want to run a binary search on the file, it seems like a real waste ...
例如:2.44444
。 我需要先到点数——就我而言是<条码>4条码>。 如何执行?
How about
( (int)(floor( fabs( num ) * 10 ) ) ) % 10
页: 1 把它交给你们,希望它能够帮助
#include<stdio.h>
int main()
{
int b;
float a;
a=2.4444; load some value
b=(int)a; typecast it into integer you get 2 into b variable
a=a-b; subtract b from a and you will get decimal point value 0.4444
a=a*10; multiplying with 10 gives 4.444
b=(int)a; now apply the same logic again
printf("%d",b); outputs 4
}
<>上<>利用这些链接书写这些功能
it could be as simple as
num*10%10
(int)(num * 10) - ((int)num) * 10
For example, let s say I want to find a particular word or number in a file. The contents are in sorted order (obviously). Since I want to run a binary search on the file, it seems like a real waste ...
最好、最小、最快、开放的来源、C/C++ 3d 提供方(在3ds max模型的支持下),而不是通用公平市价,
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