Question

如何描述县的背景,如果发言,则活动也相应。说明如何做到这一点。

  Context mContext = getApplicationContext();
  final Dialog dialog = new Dialog(mContext);
  dialog.requestWindowFeature(Window.FEATURE_NO_TITLE);

  final Button quicktab = (Button) findViewById(R.id.btnA4);
  quicktab.setOnClickListener(new OnClickListener()
  {
      @Override
      public void onClick(View v)
      {
          Button a4 = (Button)findViewById(R.id.btnA4);
          if ( a4.getBackground() == (R.drawable.quick_btn_background));      ****ERROR****
          { 
              if (this.setContentView() = this.setContentView(findViewById(R.layout.layout_24));    ****ERROR****
              {
                  dialog.setContentView(R.layout.popup_24);
              }
              else (this.setContentView() = this.setContentView(findViewById(R.layout.layout_63));    ****ERROR****
              {
                  dialog.setContentView(R.layout.popup_63);
              }
          }
          else 
          {
              finish();
          }
      }
  });

所有编码或标识错误。任何帮助都是空洞的。如果说的话,似乎不能发现与这种说法有任何关系。

****Update******** Still having errors on new code. on getBackground code, I get error: Incompatible operand types Drawable and int. on getContentView code, I get error: create method getContentView.

Context mContext = getApplicationContext(); final Dialog dialog = new Dialog(mContext); dialog.requestWindowFeature(Window.FEATURE_NO_TITLE); final Button quicktab = (Button) findViewById(R.id.btnA4); quicktab.setOnClickListener(new OnClickListener() { @Override public void onClick(View v) { Button a4 = (Button)findViewById(R.id.btnA4); if (a4.getBackground() == R.drawable.quick_btn_background) { if (this.getContentView() == R.layout.layout_24) { dialog.setContentView(R.layout.popup_24); } else if(this.getContentView() == R.layout.layout_63) { dialog.setContentView(R.layout.popup_63); } } else finish(); } });

Answer 1

请不要在您的<条码>上附上一个半殖民地,如果是的话,并加上一些失踪的封闭式母体,并且 s子应当被罚款。与此类似:

  Context mContext = getApplicationContext();
  final Dialog dialog = new Dialog(mContext);
  dialog.requestWindowFeature(Window.FEATURE_NO_TITLE);

  final Button quicktab = (Button) findViewById(R.id.btnA4);
  quicktab.setOnClickListener(new OnClickListener() 
  {
      @Override
      public void onClick(View v)
      {
          Button a4 = (Button) findViewById(R.id.btnA4);
          if (a4.getBackground() == R.drawable.quick_btn_background)
          { 
              if (this.setContentView() == this.setContentView(findViewById(R.layout.layout_24)))
              {
                  dialog.setContentView(R.layout.popup_24);
              }
              else if(this.setContentView() == this.setContentView(findViewById(R.layout.layout_63))
              {
                  dialog.setContentView(R.layout.popup_63);
              }
              else finish();
          }
    }
});

然而,我完全无法确定,你必须比较<条码>。 Don t You mean getContentView some where? 希望这一帮助,好幸运......

Answer 2

<代码>R.drawable.quick_btn_background is an numeric resources id (int or long - notfirm) while a4.getBackground( Return a Drawable. 因此,这两者的比较毫无意义。

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