Question

现在我只检查这种联系的对策:

self.client = Client()
response = self.client.get(url)
self.assertEqual(response.status_code, 200)

是否有Django-ic途径测试一个链接,看看是否实际进行了档案下载活动? 在这个问题上似乎找不到很多资源。

Answer 1

如果尿液意在生成一个文档而不是一个“热”的回复,则其<代码>连续型和/或content-disposition将有所不同。

答复对象基本上是一个字典,因此你可以这样作。

self.assertEquals(
    response.get( Content-Disposition ),
    "attachment; filename=mypic.jpg"
)

more info: https://docs.djangoproject.com/en/dev/ref/request-response/#telling-the-browser-to-treat-the-response-as-a-file-attachment

UPD: If you want to read the actual contents of the attached file, you can use response.content. Example for a zip file:

try:
    f = io.BytesIO(response.content)
    zipped_file = zipfile.ZipFile(f,  r )

    self.assertIsNone(zipped_file.testzip())        
    self.assertIn( my_file.txt , zipped_file.namelist())
finally:
    zipped_file.close()
    f.close()

Answer 2

如果您的返回是FileResponse,那么,你需要知道它会返回一个连续。

{AttributeError}AttributeError( This FileResponse instance has no `content` attribute. Use `streaming_content` instead. )

你们需要首先评价整个流层——连续,然后从缓冲中读。

import io

with io.BytesIO(b"".join(response.streaming_content)) as buf_bytes:
    loaded_response_content = buf_bytes.read()

友情链接