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PHP响应Javascript 填充田地
原标题:Trying to fill fields with Javascript, echoed by PHP

我的法典就是这样。 难道这不应该奏效? 我从我的SQL那里获得所有领域。

基本上,我想要从一页后发回信息,其号码是粗略的,这应该用来选择我的SQL的浏览数。

Here s my code from the first page:

$org = $_POST[ organization ];
header( Location:  .$admin. ?org= .$org);

接着,我关于主页的法典:

ECHO  <script> ;
ECHO  document.getElementById("orgid").value=" .$org_id. " ;
ECHO  document.getElementById("orgname").value=" .$org_name. " ;
ECHO  document.getElementById("add1").value=" .$add_1. " ;
ECHO  document.getElementById("add2").value=" .$add_2. " ;
ECHO  document.getElementById("city").value=" .$city. " ;
ECHO  document.getElementById("state").value=" .$state. " ;
ECHO  document.getElementById("zip").value=" .$zip. " ;
ECHO  document.getElementById("url").value=" .$url. " ;
ECHO  document.getElementById("email").value=" .$email. " ;
ECHO  document.getElementById("phone").value=" .$phone. " ;
ECHO  document.getElementById("contact").value=" .$contact. " ;
ECHO  document.getElementById("hours").value=" .$hours. " ;
ECHO  document.getElementById("file").value=" .$file. " ;
ECHO  document.getElementById("notes").value=" .$notes. " ;
ECHO  document.getElementById("description").value=" .$description. " ;
ECHO  </script> ;

这里还有与我的SQL联系的守则:

if (isset($_GET["org"])  && ($_GET[ org ] !==   )) {
$org = $_GET[ org ];
$resorgfull = mysql_query("SELECT org_id, org_name, add_1, add_2, city, state, zip, url, email, phone, contact, hours, file_loc, notes, description FROM organization WHERE org_id=".$org.");
if (!$resorgfull) {
    die( Invalid query:   . mysql_error());
}
问题回答

无疑有错的是,你重复文字,更应该如此:

echo "<script type= text/javascript >
";
echo "document.getElementById( orgid ).value= $org_id ;
";
...

最好......

// Close the PHP tag and output straight HTML with embedded PHP values:
?>
<script type="text/javascript">
document.getElementById( orgid ).value= <?php echo $org_id; ?> ;
...

如果这样做的话,你必须给我们更多的精力,让他们知道什么没有工作。

我看不出你们在哪里去看问结果,每行走。





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