Question

I have several threads that write to the same int. Each thread increment the integer value. What is the simple way to synchronize the increment operation. The lock statement works only on Object so i can t use it. I tried also the following:

static int number=0;

static void Main(string[] args)
    {
        ThreadStart ts = new ThreadStart(strtThread);
        new Thread(ts).Start();
        new Thread(ts).Start();
        new Thread(ts).Start();
        new Thread(ts).Start();
        new Thread(ts).Start();
        new Thread(ts).Start();
        Console.ReadLine();
    }

    public static void strtThread()
    {
        bool lockTaken = false;

        Monitor.Enter(number,ref lockTaken);
        try
        {
            Random rd = new Random();
            int ee = rd.Next(1000);
            Console.WriteLine(ee);
            Thread.Sleep(ee);
            number++;
        }
        catch (Exception ex)
        {
            Console.WriteLine(ex.Message);
        }
        finally 
        {
            if (lockTaken)
            {
             Monitor.Exit(number);
            }

        }
    }

它给我留下以下错误:

提出反对的同步方法来自不同步的法典体。

Answer 1

You can use the Interlocked.Increment Method to automically increment an integer without locking:

public static void strtThread()
{
    Interlocked.Increment(ref number);
}

If you have multiple statements, you can create an object instance that you can lock:

private static int number = 0;
private static readonly object gate = new object();

public static void strtThread()
{
    lock (gate)
    {
       number++;
    }    
}

Answer 2

你们为什么会加入<条码>。我认为,这是个问题。为此:

static Object locking = new Object();

static void Main(string[] args)
    {
        ThreadStart ts = new ThreadStart(strtThread);
        new Thread(ts).Start();
        new Thread(ts).Start();
        new Thread(ts).Start();
        new Thread(ts).Start();
        new Thread(ts).Start();
        new Thread(ts).Start();
        Console.ReadLine();
    }

    public static void strtThread()
    {
        lock(locking) {
            try
            {
                Random rd = new Random();
                int ee = rd.Next(1000);
                Console.WriteLine(ee);
                Thread.Sleep(ee);
            }
            catch (Exception ex)
            {
                Console.WriteLine(ex.Message);
            }
        }
    }

Answer 3

http://msdn.microsoft.com/en-us/library/d78zt0c.aspx” rel=“nofollow”>Interlock.Increment提供原子增量。 http://msdn.microsoft.com/en-us/library/5kczs5b5.aspx” rel=“nofollow”>Interlock ,一般而言,“为多环相传的变量提供原子操作

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