Question

我有以下职能:f(x,y)= Exp(-x^2-y^-2)(x^2+y^2)。我愿研究一下将这一职能投向MATLAB的轴心。

任何关于这样做的最佳方法的想法?

Answer 1

例如:

xs = [];
ys = [];
zs = [];
for x = -10:0.1:10
    for y = -10:0.1:10
        xs = [xs x];
        ys = [ys y];
        z = f(x,y);
        zs = [zs z];
    end
end
figure; plot3(xs,ys,zs);  %plots the full function over both dimensions
figure; plot(xs,zs, rx ); %plots the projection onto the x axis
figure; plot(ys,zs, rx ); %plots the projection onto the y axis

这在范围上——10至10沿x和 y,但可以相应改变。

Answer 2

@Amro有一个很大的解决方案,但你还可以从MAABTL中央卷宗交换处看Scott Hirsch的黑体。检查:

>> f = @(x,y) exp(-x.^2 -y.^(-2)).*(x.^2+y.^2);
>> [X,Y] = meshgrid(-10:0.5:10,-10:0.5:10);
>> surf(X,Y,f(X,Y))
>> xlim([-11,11])
>> ylim([-11,11])
>> shadowplot x
>> shadowplot y

Answer 3

http://www.mathwork.com/help/techdoc/ref/view.html” rel=“nofollow noreferer”>view,看2D-projection on the x-axis:

f = @(x,y) exp(-x.^2 -y.^(-2)).*(x.^2+y.^2);
[X,Y] = meshgrid(-10:0.5:10,-10:0.5:10);
surf(X,Y,f(X,Y))
view(90,0), shading interp
xlabel X, ylabel Y, zlabel Z

友情链接