Question

我有以下几类:

public class A
{
   public List<object> MyItems { get; set; }
   public Color Color { get; set; }
   public object MyItem { get set; }
}

每一例A均可有n。 MyItems.

鉴于一份名单,我需要以色谱加以过滤,并制定新的清单,其中为MyItems收集的每个要素创建了一个新的A案例。

List<A> Aitems = originalItems.Where(b => b.color == color)
                              .Select(b=>
{
    A aItem = b;
    // Problem below. Is there a way to create more
    // aItems for every object in MyItems collection?
    b.MyItem = b.MyItems[0];
    return aItem;
}).ToList();

是否有办法利用准则收集MyItems的每一物体制造更多的系统,或者我是否应当使用标准表格?

Answer 1

你们是否寻求这样的东西?

var query = from b in originalItems
            where b.Color == color
            from item in b.MyItems
            select new A
            {
                MyItems = b.MyItems,
                Color = b.Color,
                MyItem = item,
            };

var result = query.ToList();

Answer 2

假设你想为<代码>中的每一项目创造新的A。具体彩色物体的MyItems,你可以这样做:

from a in originalItems
where a.color == color
from myItem in a.MyItems
select new A { /* not sure what you want here */ }

Answer 3

这将使你们能够从原计划获得一份清单,其中你希望:

var items = (from a in OriginalItems
              where a.Color == color
              from item in a.MyItems
              select item).ToList();

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