Question

我有简单的文字:

now = datetime.datetime.now()
print "%d%d%d%d%d" % ( now.year, now.month, now.day, now.hour, now.minute )

结果:

20111124149

How to get 结果:

201111241409

?

Answer 1

具体说明数字应为2,零增:

now = datetime.datetime.now()
print "%04d%02d%02d%02d%02d" % ( now.year, now.month, now.day, now.hour, now.minute )

如果我们打破其中一个组成部分,我们就会:

% marks the start of a substitution target.
0 makes the result zero-padded.
2 means, that the result should be 2 characters wide.
d means that it s a decimal value.

Further information:

String Formatting Operations in the Python manual

Answer 2

方法一:使用<代码>%02d而不是%d。这一垫了两顶,头零。

print "%02d%02d%02d%02d%02d" % (now.year, now.month, now.day, now.hour, now.minute)

方法2,正确方式:使用datetime.strftime。

print now.strftime( %Y%m%d%H%M )

For explanation of the format string, see strftime() and strptime() Behavior in the Python docs.

Answer 3

I d suggest this approach:

print "{0:02d}{1:02d}{2:02d}{3:02d}{4:02d}".format(now.year, now.month, now.day, 
                                                   now.hour, now.minute)

The format -method should be favor over the original Formatting syntax. http://docs.python.org/library/string.html#format-string-syntax” rel=“nofollow” 。

Answer 4

now = datetime.datetime.now()
print "%d%02d%02d%02d%02d" % (now.year, now.month, now.day, now.hour, now.minute)

Further information:

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