Question

I just started learning Python... I am writing a simple program that will take in integers and keep an unsorted and sorted list. I m having a problem with the sorted list part... I m getting an error when comparing the values of elements within the list. Where I get the error is the following line: "if sortedList[sortcount] > sortedList[count]:". I get "TypeError: unorderable types: list() > int()".

这里是法典的一部分...... 我不相信什么是错的。

numberList = []
sortedList = []
count = 0
sum = 0

....(skip)....

sortcount = 0
sortedList += [ int(userInput) ]
while sortcount < count:
    if sortedList[sortcount] > sortedList[count]:
        sortedList[count] = sortedList[sortcount]
        sortedList[sortcount] = [ int(userInput) ]  
    sortcount+=1

Answer 1

您:

sortedList[sortcount] = [ int(userInput) ]

应:

sortedList[sortcount] = int(userInput)

否则,你就会在职位上增加一个名单,给你留下错误。

BTW,在休息前第一行,最好写上字。

sortedList.append(int(userInput))

Answer 2

请考虑使用:

sorted(numberList)

编制您的分类清单。很多,更简单地说,不需要重新发明轮椅。

Example:

>>>unSorted = [3, 4, 1, 5]
>>>unSorted
[3, 4, 1, 5]
>>>sortedList = sorted(unSorted)
>>>sortedList
[1, 3, 4, 5]

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