Question

我有一张需要用5种颜色的梯度来描述的光线图像。轻型粉碎机应当从梯度中取出更光明的颜色,黑暗的颜料应更黑暗。

If the gradient starts with yellow and ends with red, then white pixels would be yellow and black pixels red with everything in between along the gradient.

能否与科罗拉·马基斯一起进行?

Answer 1

What you want is in the simplest case a linear interpolation between 5 points in 3d. A direct color gradient between two colors {r1,g1,b1} and {r2,g2,b2} is, as you would walk onto the line in 3d which connects the points {r1,g1,b1} and {r2,g2,b2}. When your gray-values are in the interval [0,1], then you would want to have the color {r1,g1,b1} if you have a gray-level 0 and {r2,g2,b2} if you have a gray-level 1. The question is how to calculate the colors in between:

考虑简单的学校病媒分析。 c1 点{r1,g1,b1}, c2为{r2,g2,b2}。 1. 着手处理1项病媒,并朝着2c1:

* E/CN.6/2009/1。

或同等

http://www.un.org

Remenber, gray必须位于间隔[0,1]。否则,你就不得不重新进行。这在两点之间是简单的直线干涉,当然可以延伸到你们想要的众多肤色。

对5个颜色而言,这种办法基本相同。这里有5种随机选择的颜色:

{{0.273372, 0.112407, 0.0415183}, 
 {0.79436,  0.696305, 0.167884}, 
 {0.235083, 0.999163, 0.848291}, 
 {0.295492, 0.780062, 0.246481}, 
 {0.584883, 0.460118, 0.940826}}

“entergraph

你们必须知道的两项重要内容:

如果你想有某种光彩价值,你首先需要提取两个环绕点。例如,如果你希望有光线0.1的颜色,那将是第一个和第二点。
您根据您在梯度中使用的颜色重新计算其光度值。看看图像,有5个颜色,有4个不同的2点干涉间隔。当你想进行上述彩色公式工作时,你必须重新计算每张彩色的光价,以达到[0,1]。

Remark: This is of course not the solution for the implementation in C#, but your question suggested, that creating a color-image of the same size was not your problem. Calculating the color-values for each gray-value is the key for your colorization.

Answer 2

你提到“五色”,但也提到从红色到黄色的梯度。

为了说明基本想法,我们可以从一阵列中产生一个阵列,星阵列代表了原形象的8倍光值。

grayscale value 0 (black) maps to red, which is Color.FromArgb(255,0,0)
grayscale value 255 (white) maps to yellow, which is Color.FromArgb(255,255,0)

鉴于光度值(8比值),寻找新的梯度(r,g,b)如下:

Set the Red component to 255
Set the Blue component to the original gray value (0 - 255)
Set the Green component to 0

从一阵式向科罗列转变的样本代码:

byte[] bytes = getImageBytes();
Color[] colors = new Color[bytes.Length];  

for(int i = 0; i < bytes.Length; i++)
{
    colors[i] = Color.FromArgb(255, bytes[i], 0);
}

为了迅速开展这项工作,使用“锁定/锁定借方”法,并直接操纵随附价值。

http://msdn.microsoft.com/en-us/library/5ey6h79d.aspx

Answer 3

你可以简单地把光线图像的所有粉碎,并掌握其光彩和阿尔法价值(简言之,使用LINQ)。然后,你带上了你所希望的颜色,并利用了它的威爱和饱和布。

Now you create a new color by taking the Gray.Alpha, Color.Hue, Color.Saturation and a combination of Gray.Brightness and Color.Brightness and apply this color to the pixel in the grayscale image.

第一个trick块是从阿尔法、胡伊、饱和和布律制成色体,但你可以简单地拿到这一功能;-。

最后一部分是将灰色和彩色混为一谈,留给读者。

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