Question

我有这种档案:

塞族共和国的分离者是一空一线。

如果存在双重空白线,我们必须代之以如下方式: 1 0<>code>,$1, 即之前增加的“编号”, 编号1 0*。



If the separator is empty line + 1 empty line we have to increase the $1 by 1.
If the separator is empty line + 2 empty line we have to increase the $1 by 2.
...

and I need to get this output:

1 0 1

2 0 3
2 1 2

3 0 3

4 0 1
4 1 1
4 2 1
4 3 1

5 0 1

6 0 0 

7 0 0

8 0 1

9 0 0

10 0 1

11 0 1


提前感谢!

Answer 1

你可以尝试这样的东西。 <><>>> 这样做的好处是,你的输入文件不需要一个空洞的线。

awk -v RS="" -v ORS="

" -v OFS="
"                     
BEGIN{getline; col=$1;line=$0;print line}
$1==col{print $0;next }
($1==col+1){print $0;col=$1;next}
{x=$1;y=$0; col++; while (col < x) {print col" 0 0";col++};print y;next}  file

Input File:

[jaypal:~/Temp] cat file
1 0 1

2 0 3
2 1 2

3 0 3

4 0 1
4 1 1
4 2 1
4 3 1

5 0 1



8 0 1


10 0 1

11 0 1

Script Output:

[jaypal:~/Temp] awk -v RS="" -v ORS="

" -v OFS="
"                     
BEGIN{getline; col=$1;line=$0;print line}
$1==col{print $0;next }
($1==col+1){print $0;col=$1;next}
{x=$1;y=$0; col++; while (col < x) {print col" 0 0";col++};print y;next}  file
1 0 1

2 0 3
2 1 2

3 0 3

4 0 1
4 1 1
4 2 1
4 3 1

5 0 1

6 0 0

7 0 0

8 0 1

9 0 0

10 0 1

11 0 1

Answer 2

awk  NF{f=0;n=$1;print;next}f{print ++n " 0 0"}{print;f=1}  ./infile

Output

$ awk  NF{f=0;n=$1;print;next}f{print ++n " 0 0"}{print;f=1}  ./infile
1 0 1

2 0 3
2 1 2

3 0 3

4 0 1
4 1 1
4 2 1
4 3 1

5 0 1

6 0 0

7 0 0

8 0 1

9 0 0

10 0 1

11 0 1

Explanation

NF{f=0;n=$1;print;next}: if the current line has data, unset flag f, save the number in the first field to n, print the line and skip the rest of the script
{print;f=1}: We only reach this action if the current line is blank. If so, print the line and set the flag f
f{print ++n " 0 0"}: We only execute this action if the flag f is set which only happens if the previous line was blank. If we enter this action, print the missing fields with an incremented n

Input File:

Script Output:

Output

Explanation

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