SELECT 3 AS x, 5 as y, (x+y) as z
期望的结果;
x y z
3 5 8
结果;
#1054 - Unknown column x in field list
SELECT 3 AS x, 5 as y, (x+y) as z
期望的结果;
x y z
3 5 8
结果;
#1054 - Unknown column x in field list
《选任考试法》条款(及各栏)的评审同时进行,且不按具体顺序进行。 也就是说,在你想要的同一点,X栏和 y栏还不存在。
SELECT
(x+y) as z
FROM
(
SELECT 3 AS x, 5 as y
) t;
SELECT @x:=3 as x, @y:=5 as y, (@x + @y) as z;
为什么你们想要这样做?
由于你的询问使用了不变值,因此这项工作是罚款的。
SELECT 3 as x,5 as y,(3+5) as z;
因为你可以使用作为甄选者一部分新设立的第十号。 而是使用你的常态,因为你不需要别的东西或像其他答案一样的临时桌子。
如果你的实际问题有所不同,请说明,那么,或许你只是想到这个错误。
SELECT 3 AS x, 5 as y, (3+5) as z
可在<代码>x和y
之前通过查询引擎加以界定。 这意味着z
存在于x
和y
之前,因此有错误。
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