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为什么这种问问问问问不做什么?
原标题:Why that query isn t working as i expected ?
  • 时间:2012-01-16 10:01:03
  •  标签:
  • mysql
SELECT 3 AS x, 5 as y, (x+y) as z

期望的结果;

x  y  z
3  5  8

结果;

#1054 - Unknown column  x  in  field list  
最佳回答

《选任考试法》条款(及各栏)的评审同时进行,且不按具体顺序进行。 也就是说,在你想要的同一点,X栏和 y栏还不存在。

SELECT
   (x+y) as z
FROM
    (
    SELECT 3 AS x, 5 as y
    ) t;
问题回答

你可以指这样一栏。 提 出

SELECT (tmp.x + tmp.y) as z FROM (SELECT 3 AS x, 5 as y) tmp

Ref.:

SELECT @x:=3 as x, @y:=5 as y, (@x + @y) as z;

为什么你们想要这样做?

由于你的询问使用了不变值,因此这项工作是罚款的。

SELECT 3 as x,5 as y,(3+5) as z;

因为你可以使用作为甄选者一部分新设立的第十号。 而是使用你的常态,因为你不需要别的东西或像其他答案一样的临时桌子。

如果你的实际问题有所不同,请说明,那么,或许你只是想到这个错误。

SELECT 3 AS x, 5 as y, (3+5) as z

可在<代码>x和y之前通过查询引擎加以界定。 这意味着z存在于xy之前,因此有错误。





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