Question

这简言之,我试图做的事情,我只想混淆右yn。

我希望我能这样做:

struct myStruct
{
   functionPointer myPointer;
}

Then I have another function somewhere else that passes a function to a function and returns an instance of my struct. Here s what it does:

struct myStruct myFunction(int (*foo) (void *))
{
   myStruct c;
   c.myPointer = foo;
   return c;
}

我如何使这项工作真正发挥作用? • 正确yn子:

Declaring a function pointer in my struct (obviously functionPointer myPointer; is incorrect)
Assigning a function s address to that function pointer (pretty sure c.myPointer = foo is incorrect)?

Answer 1

它与职能点的任何其他情况完全不同:

struct myStruct
{
   int (*myPointer)(void *);
};

虽然经常使用<条码>tdef,但很少使用。

Answer 2

更多或更少:

struct myStruct
{
    struct myStruct (*myPointer)(int (*foo)(void *));
};
typedef struct myStruct myStruct;

<代码>c.myPointer 更正请在一份备忘录内,但您须交还一份结构副本,而不是一份标出现已消失的当地变量的点码<>c>。

struct myStruct
{
    struct myStruct (*myPointer)(int (*foo)(void *));
};
typedef struct myStruct myStruct;

struct myStruct myFunction(int (*foo) (void *))
{
    myStruct c;
    c.myPointer = foo;
    return c;
}

这部法律汇编,但汇编者(合情合理)称,“条形状”/条形形实际上不是正确的类型。因此,问题是——结构中的职能点的正确类型是什么? 这取决于你们想要做什么。

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