What s the probability for the clash for the md5 algorithm? I believe it is extremely low.
如果你不试图故意制造碰撞,那么你需要掌握大约2兆赫64的数值,以便平均相互发生一次碰撞。 哈希的碰撞与。
如果你看上两种任意的数值,碰撞概率仅为2-128。
问题5在于,制定两种具有相同价值的不同的文本相对容易。 但这需要蓄意攻击,而且无意中发生。 即便是蓄意攻击,现在也不可能找到一个与某一特定的散射相匹配的简单文本。
简而言之5为非安全目的安全,但在许多安全申请中被打破。
它产生128倍的价值。 因此,意外冲突率应为2-64(因出生日而死亡)。
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