Question

我试图将用户选择写进文本档案。这一工作是完美的。使用者的选择也一样:

页: 1

2 P-4, 2 P-3, 2 FS, 2 NS

3

..

def write_log(name, total):
   # This writes a passed info into text
   logfile = open("text.txt", "a")

   towrite = name
   towrite += " "
   towrite += total
   towrite += "
"

   try:
       logfile.write(towrite)
   finally:
       logfile.close()

   return write_log

www.un.org/Depts/DGACM/index_spanish.htm

I am trying to replace user choice with another names. something like this:

www.un.org/Depts/DGACM/index_spanish.htm

change = [(页: 1, triangle), (2 P-4, 2 P-3, 2 FS, 2 NS, square), (3, rectangle), (4, pentagon)]

www.un.org/Depts/DGACM/index_spanish.htm

when i do this it does not work

www.un.org/Depts/DGACM/index_spanish.htm

def write_log(name, total):
   # This writes a passed info into text
   change = [(页: 1, triangle), (2 P-4, 2 P-3, 2 FS, 2 NS, square), (3, rectangle), (4, pentagon)]
   for search, replace in change:
      name = name.replace(search, replace)
   logfile = open("text.txt", "a")

   towrite = name
   towrite += " "
   towrite += total
   towrite += "
"

   try:
       logfile.write(towrite)
   finally:
       logfile.close()

   return write_log

Answer 1

我将使用字典:

def write_log(name, total):
   change = {1:  triangle , 2:  square , 3:  rectangle , 4:  pentagon }

   name = change.get(name,  other )
   towrite = "%s %d
" % (name, total)
   logfile = open("text.txt", "a")

   try:
       logfile.write(towrite)
   finally:
       logfile.close()

Answer 2

这是我使用的:

def write_log(name, total):
    #{n} is better than to replace a number if it s user input,
    #where n is the index of each item in change. I.E {0} == change[0] == "triangle"
    change = ["triangle", "square", "recrangle", "pentagon"]#remember that {n} refers to a position in this list.
    towrite = "%s %s
" % (name.format(*change), total)
    with open("text.txt", "a") as logfile:#With closes a file automatically for you, in fewer lines.
        logfile.write(towrite)

如果你想完全替代你的话:

towrite = "%s %s
" % (name.format(*change), total.format(*change))

如果“变化”不可行,你可以不包装清单(名称:format(“triangle”、“rectangle”)。

Good:

友情链接