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Parse and reformat a datetime string (6 answers)

Closed last year.

I have a string with a date which is in this format MMDDYYYY (ie. 01132012, 01142012 etc.)

我需要在一页上做一些事情,如果从现在起到14天左右。

ie. Today is 01132012, so any strings with 12312011 or a less date are going to be showing something on a page.

谁能帮助? 我受审

echo date("d/m/Y", strtotime( 01142012 ));

但没有结果。

Answer 1

您可以使用购买力平价的时段。

<?
  // current date
  $now = new DateTime();

  //your date
  $date = DateTime::createFromFormat( mdY ,  01142012 );

  // calculate difference 
  $diff = $now->diff($date);

  ...

  // output the date in format you want
  echo $date->format( d/m/Y );
?>

EDIT:我刚刚认识到,你的格式没有一种得到php支持的形式。因此,你必须使用替代物体。

Answer 2

我更喜欢使用平时。

<?
$dt = strptime( 01142012 ,  %m%d%Y );
echo sprintf("%02d/%02d/%04d", $dt[ tm_mday ], $dt[ tm_mon ]+1, $dt[ tm_year ]+1900);

如果你使用PHP5.3或以上,你也可以使用日期_parse_ from_format()

Answer 3

有多少次子午餐?

$string =  01142012 ;
$time = mktime(0, 0, 0, 
          substr($string, 0, 2),
          substr($string, 2, 2),
          substr($string, 4, 4)
        );
 echo date( d/m/Y , $time);

Answer 4

try date( m-d-y , strtotime( 01142012 ));

也可以尝试类似的东西;

$var = strtotime( 01142012 );
$var2 = date ( F j, Y , $var);

Answer 5

你提出的1 0142012年建议不能用时间加以限定,因为作为答案,这并不有效。为了把这个日期改为一个有效日期,你需要添加斜体或 da,以区分数字。

最容易的方式是将日期与浮标或斜).相储存,例如从现在起在数据库中储存01-14-2012年或01/14/2012年,或者你将不得不自行创建功能,将数字转换成实时的有效形式。

你们可以这样做:

function makeValidDate($date) {

   $valid_date = array();
   $array = str_split($date); //split characters up

   foreach($array as $key => $character){
       if($key==2 || $key==4){
           $character =  - .$character; //add relevant formatting to date
           $valid_date[] = $character; //add this to the formatted array
       }
       else{
           $valid_date[] = $character; // if not dashes or slashes needed add to valid array
       }
   }

   return implode($valid_date); // return the formmatted date for use with strtotime
}

届时,你可以做到:

$valid_date = makeValidDate( 01142012 );    
echo date("d/m/Y", strtotime($valid_date));

I haven t tested this but you should get a good idea of what to do.

EDIT: Capi s idea is a lot cleaner!!

Answer 6

try "preg_match(pattern,string on wich the pattern will be aplied)"; http://www.php.net/manual/en/function.preg-match.php you can also define an offset. so first take te first 2 digits. than take the other 2 digits and after that get the other four digits. after that place them in one string. after that use maketime,strtotime,date. this kind of stupid solution but i only thought of that. hope this will help

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