Question

class Test:
       def func():
           print( func )
test1 = Test()
test2 = Test()

test1.func()  #TypeError: fun1() takes no arguments (1 given)
test2.newfunc = Test.func
test2.newfunc()#It goes well

# update part
def foo(self):
    pass
Test.foo = foo
test1.foo # it is bound method
test2.foo = foo
test2.foo # it is function
# end

Is there any difference between the two ways ? Thanks.

# update part
def foo(self):
    pass
Test.foo = foo
test1.foo # it is bound method
test2.foo = foo
test2.foo # it is function
# end

请注意,重要的是,检索应在班级而不是班级进行。

Answer 1

调查范围:

>>> test1.func
<bound method Test.func of <__main__.Test instance at 0x800f211b8>>
>>> Test.func
<unbound method Test.func>

然后使用界定的限量方法(test1.func,就我们的情况而言),这一呼吁实际上是作为进行的。



http://docs.python.org/fer/datamodel.html#index-867“rel=“nofollow”>。 灰色数据模型。




<><>Edit>/strong>

以上是第2.6段的内容。 在这种情况下,产出如下:

>>> test1.func
<bound method Test.func of <__main__.Test object at 0xb747624c>>
>>> Test.func
<function func at 0xb74719ec>


As you see, Test.func is a simple function, so no  magic  will be added while calling it.

Answer 2

Methods of a class that are called on an instance of the class are passed the instance reference as an argument automatically. Thus, they re usually declared with a self argument:

class Test:
       def func(self):
           print( func )

test1 = Test()
test1.func() # self = test1

友情链接