Question

There is one question I am working on and got a very close answer... basically, the question is that you get two dictionaries and you have to find elements that intersect from both dictionaries and then create those elements (one same key from both dicts and two values from both dics) in a new dictionary.

a = { A :17, B :31, C :42, D :7, E :46, F :39, G :9}
b = { D :8, E :3, F :2, g :5}

def intersect(a,b):
    c = set(a).intersection(set(b))
    d = {}
    for i in c:
        if i in a:
            d[i] = int(a[i]),int(b[i])
    return d

OUTPUT: { E : (46, 3),  D : (7, 8),  F : (39, 2)}

我想获得这样的产出,如{E:46、3、D:7、8、F:39、2}

How do I get rid of the parentheses around the values?

Answer 1

你们撰写的《守则》根本就取得了任何成果。然而,如果你想去除母子,那么你就可以这样做。

str(intersect(a, b)).replace( ( ,   ).replace( ) ,   )

更简明、更高效

str(intersect(a, b)).translate(None,  () )

Answer 2

你看到的产物是你dict的 representation。你建造的(而且,就我所知,你正确地建造了它——这是你想要的——是绘制成像图的关键。奶粉是 t,它们用括号印制。

就像你想要的那样,它是一种采用你的字典和印刷的方法,其形式是具体的。

仿照这一点,你想用字典来说明:

def dictionary_printer(d):
    print "{%s}" %  ,  .join(
        [(" %s : %s" % (key,  ,  .join(map(str,value))))
        for key, value in d.items()]
    )

友情链接