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Closed 9 years ago.

每个我都做了一个小的工作,需要2D阵列的点子,并用直线一字填写。我用字逐句填补我的2D阵列。我认为,在我试图印刷我的阵列时,它的工作是细微的,但只是空洞的。任何人都能够帮助我,如果我错了。

Thanks

void create_table(char *key ,char (*table)[5]){

    int row=0, col=0;
    while(*key){
        *(table + row++)[col++] = *key++; 
                printf("%c" , table[0][0]); // Here I got seg fault

        if(col == 4){
            col=0;
            row++;      
        }

    }       

}

//===================================

int main(){
    char table[5][5];
    create_table("monarchy" ,table);
        return 0;

}

Answer 1

 *(table + row++)[col++] = *key++;

不应成为“增长”,而只是“增长”。你已经在其他地方重新增加“增长”。

Answer 2

Perhaps, a little more readable:

void create_table(char *key ,char (*table)[5])
{
    int len = strlen(key);

    int row=0, col=0;
    while (len--)
    {
        table[row][col] = *key;
        printf("%c
" , table[row][col]); 
        col++;
        key++;

        if (col == 4)
        {
            col = 0;
            row++;      
        }

    }

}

友情链接