Beginner Haskell 在这里学习。 我解决了Euler项目问题1, 数额比1 000多3或5人,但我期待着“更像英语”的功能代表。
我设立了一个称为多个单位的职能。
multiples::(Integral a) => a -> [a]
multiples a = map (*a) [1..]
我高兴,但我希望说,
multiples of::(Integral a) => a -> [a]
multiples of a = map (*a) [1..]
更像英文,但在“对”投入方面,我有一小差错。
我想我的职能声明读作这样的内容:
sum of multiples of::(Type)=>Type->Type
任何希望?
这种说法不言而喻,但你只能界定“词”,无视你“英文”职能中的论点:
by = ()
multiply a _ b = a*b
multiply 10 by 12
--120
但是,在您的榜样中,作为的<>编码>,你从中转出一个关键词(载于)。
By the way, here is another way of defining multiples:
multiples_of = scanl1 (+) . repeat
take 10 $ multiples_of 12
--[12,24,36,48,60,72,84,96,108,120]
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