Question

i 熟悉javascript permanent expression to notcompa. 在给予体力时(具有任何种类的特性),我想将其分为两条标语:“/”和“/”。 i 做了以下工作:

var patt = /.*[^"//"]/gm;
patt.exec(str);

但是,这似乎与引语之间特性的任何发生相吻合,即“/”和“/”。如何做到这一点?

Answer 1

当你开始使用<代码>^的特性类别时(如您在<代码>[^”/>>中已有的),是指“除所列特性外的任何特性”。 http://www.un.org/Depts/DGACM/index_chinese.htm

If you re trying to match the text between two slashes (//) and one backslash () (as per your question; you later made a comment suggesting it s two backslashes, I address that later), then:

var match = str.match(///(.*?)\/);    // Match between // and

请注意,由于冲突是经常表达的限定词,我们必须避免冲突,因为反弹是越狱。

以上指“两lash,后一lash为零或以上,之后为后lash”。 www.un.org/Depts/DGACM/index_french.htm 非消费性(因此,其消费的特性可能满足这一表述)。 <>代码>( 创建capture group<>em>,在对应标的中,该组将获得与该职位相应的特性。

例:

test("foo"); test("foo //bar"); test("foo //bar\"); test("foo //bar\ baz"); test("bar\ baz"); test("//bar\ baz"); test("foo //bar\ baz \ more \ more"); function test(str) { var m = str.match(///(.*?)\/), cap = (m && m[1]) || "<em>nothing</em>"; display("Str: <code>" + str + "</code>: Captured <code>" + cap + "</code>"); }

产出:

范围:<0>

Str: foo /bar: Captured nothing

Str:foo /bar: 页: 1

范围: 页: 1

Str: bar baz : Captured nothing<>>>。

Str:/bar baz: 页: 1

Str:foo /bar baz more: 页: 1

Live copy

Or for two backslashes:

var match = str.match(///(.*?)\\/); // Match between // and \

Live copy (the output is the same, just with two backslashes)

Some reading on JavaScript regular expressions:

The spec (that s a handy linkable HTML rendering of it; the canonical one is a PDF here)

Mozilla s excellent RegExp page

Answer 2

怎么说

var tokens = str.split(///|\\/);

友情链接