Question

我有这样一部法典。

host =  http://www.bing.com/search?q=%s&go=&qs=n&sk=&sc=8-13&first=%s  % (query, page)
req = urllib2.Request(host)
req.add_header( User-Agent , User_Agent)
response = urllib2.urlopen(req)

并且当我提出疑问时,像“狗”这样一字就会产生以下错误。

response = urllib2.urlopen(req)
File "/usr/lib/python2.7/urllib2.py", line 126, in urlopen
return _opener.open(url, data, timeout)
File "/usr/lib/python2.7/urllib2.py", line 400, in open
response = meth(req, response)
File "/usr/lib/python2.7/urllib2.py", line 513, in http_response
 http , request, response, code, msg, hdrs)
File "/usr/lib/python2.7/urllib2.py", line 438, in error
return self._call_chain(*args)
File "/usr/lib/python2.7/urllib2.py", line 372, in _call_chain
result = func(*args)
File "/usr/lib/python2.7/urllib2.py", line 521, in http_error_default
raise HTTPError(req.get_full_url(), code, msg, hdrs, fp)
urllib2.HTTPError: HTTP Error 400: Bad Request

Can anyone point out what im doing wrong? Thanks in advance.

Answer 1

The reason that "the dog" returns a 400 Error is because you aren t escaping the string for a URL.

如果是:

import urllib, urllib2

quoted_query = urllib.quote(query)
host =  http://www.bing.com/search?q=%s&go=&qs=n&sk=&sc=8-13&first=%s  % (quoted_query, page)
req = urllib2.Request(host)
req.add_header( User-Agent , User_Agent)
response = urllib2.urlopen(req)

它将开展工作。

然而,我高度建议你使用,而不是使用urllib/urllib2/httplib。这对你来说,这非常容易,而且会给你带来所有这一切。

This is the same code with python requests:

import requests

results = requests.get("http://www.bing.com/search", 
              params={ q : query,  first : page}, 
              headers={ User-Agent : user_agent})

Answer 2

您需要使用<代码>urllib.quote()来回答问题:

query = urllib.quote(query)
host =  http://www.bing.com/search?q=%s&go=&qs=n&sk=&sc=8-13&first=%s  % (query, page)

如有必要,URL escaping将空间转换为big dog至big%20dog。

Answer 3

这方面的一个例子是如何使用血缘。请求在A/63/13和3。

import urllib.request
import json
from pprint import pprint

url = "some_url"

values = {
    "first_name": "Vlad",
    "last_name": "Bezden",
    "urls": [
        "https://twitter.com/VladBezden",
        "https://github.com/vlad-bezden",
    ],
}


headers = {
    "Content-Type": "application/json",
    "Accept": "application/json",
}

data = json.dumps(values).encode("utf-8")
pprint(data)

try:
    req = urllib.request.Request(url, data, headers)
    with urllib.request.urlopen(req) as f:
        res = f.read()
    pprint(res.decode())
except Exception as e:
    pprint(e)

Answer 4

我也遇到了同样的问题。问题在于确定的方法是不适当的。如果你在urllib2.urlopen()中包含长条码数据,那么该方法应当被定为POST,如果你排除,则该方法应当是GET。因此,你如何确定这一方法如下:

POST申请

request_object = urllib2.Request(url)
method = ("POST", "GET")
request_object.get_method = lambda: method[0] #If method is set to POST
url_handle = opener.open(req, data) #If method is set to POST

GET 请求

request_object = urllib2.Request(url)
method = ("POST", "GET")
request_object.get_method = lambda: method[1] #If method is set to GET
url_handle = opener.open(req) #If method is set to GET

这将使你的要求方法符合适当的必要方法。

友情链接