I can use SUM(xpath) to sum all node values, but I also have a requirement to sum all positive node values, all negative node values and all node values treating them as absolute values. Is this possible with XSLT?
为了概括所有积极的节点价值,你可以做到:
<xsl:value-of select="sum(//*[. > 0])" />
为了概括所有消极的节点价值,你可以做到:
<xsl:value-of select="sum(//*[. < 0])" />
To sum the absolute values of the numbers, you can do:
<xsl:value-of select="sum(//*[. > 0]) - sum(//*[. < 0])" />
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