我有一席之地。
let String = " Test ";
I need an output as below:
产出=试验
I have tried using trim(), trimstart(), trimend()
Only one space has been removed using these scalar functions.
采用replace_regex(资料来源,lookup_regex, rewrite_pattern)创建工作现场。
Pass the string value as source, lookup_regex as " " (nothing but blank spaces), rewrite_pattern as "" (replace with no space)
<<>Example>>:
投入:让步=“试验”;/间隔期为11
- 申请编码
为了取代不止一个拖车和主要空间特性,我们可以使用定期表述<代码>[trim(@'[ ]+”,<string_to_replace>)]
let String = " Te. se st. ";
print original_string = String replacing_all_space_via_regex= trim(@"[ ]+",String)
//Other possible methods to replace just the single occurrence of space
//print original_string = String, replacing_single_space_via_space_character = trim(@" ", String)
//print original_string = String replacing_single_space_via_regex = trim(@"[ ]",String)
拆除所有空间:
let String = " s idan mor ";
print replace_string(String, " ", ""); // output will be "sidanmor"
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