Question

I don t know if there following if possible. I have:

type A struct {
  Val int
}

以及

type B struct {
  Val *int
}

接着,我有这一努力。

func main() {
  b := B{Val: new(int)}
  *b.Val = 1

  a := A{Val: *b.Val}
}

What I want to achieve is that the variable a gets initialized with its zero values, hence its Val being 0 in case *b.Val = nil without having to check with an if condition. This is a very simplified version 以及 the reason I am trying to do this is that my B struct has many properties that might or might not be filled by different entities. Such properties make more sense as nil in case they are not filled 以及 I am trying to avoid checking with an if condition for each one of them if they are nil before assigning their non-nil value or the zero value to the properties of A

Answer 1

只要你开始做任何事情,就自动产生有违约价值的变数。您可以简单地使用下文中任何一个提到的内容:

a := new(A)
a := A{}
var a A

以上所有因素都将使其变数变得零。

友情链接