我愿在我的弗拉茨克申请中加入一个编集器。 是否有普遍接受的办法这样做?
Is there a way to force Django models to pass a field to a MySQL function every time the model data is read or loaded? To clarify what I mean in SQL, I want the Django model to produce something like ...
我愿在我的弗拉茨克申请中加入一个编集器。 是否有普遍接受的办法这样做?
推广(使用webassets/ Library)可用于此目的。 http://pypi.python.org/pypi/pyScs” rel=“nofollow noreferer”>pyScsSCSS(implemented in-030)编辑:
from flask import Flask, render_template
from flask_assets import Environment, Bundle
app = Flask(__name__)
assets = Environment(app)
assets.url = app.static_url_path
scss = Bundle( foo.scss , bar.scss , filters= pyscss , output= all.css )
assets.register( scss_all , scss)
模板包括:
{% assets "scss_all" %}
<link rel=stylesheet type=text/css href="{{ ASSET_URL }}">
{% endassets %}
还将以减速方式汇编特别安全局的文件。
pyScs只支持SCSS syntax,但还有其他过滤器(sass
,scs
和compass
),这些过滤器使用原来的Ruby。
自这一问题在2013年解答以来,一些事情发生了变化。
你们可以拥有安装在玩具的同时的c,并期望过滤器像在接受的答复中那样工作。
scss = Bundle( foo.scss , bar.scss , filters= pyscss , output= all.css )
我的错误是:
File "/home/sri/crap/example/flask/lib/python2.7/site-packages/webassets/filter/pyscss.py", line 110, in setup
scss.config.STATIC_ROOT = self.static_root or self.ctx.directory
您必须去除胎体(即pip uninstall scss
),并确保安装 p具(即pip stalpyscs
)。
2. 又注意到为了让玩具发挥作用,你必须确定一些环境变量:
app = Flask(__name__)
assets = Environment(app)
assets.url = app.static_url_path
scss = Bundle( index.scss , filters= pyscss , output= all.css )
assets.config[ SECRET_KEY ] = secret!
assets.config[ PYSCSS_LOAD_PATHS ] = assets.load_path
assets.config[ PYSCSS_STATIC_URL ] = assets.url
assets.config[ PYSCSS_STATIC_ROOT ] = assets.directory
assets.config[ PYSCSS_ASSETS_URL ] = assets.url
assets.config[ PYSCSS_ASSETS_ROOT ] = assets.directory
assets.register( scss_all , scss)
see the documentation on the pyscss filter for more info: http://webassets.readthedocs.io/en/latest/builtin_filters.html#pyscss
我希望这节省了其他人很多时间,因为我整整天浪费了。
目前,对这一问题有更好的处理方式,见。 Flask-Scs。
You just have to install it: pip install Flask-Scss
在对申请进行配置后,对物体进行分类(见manage.py
文档):
from flask import Flask
from flask.ext.scss import Scss
app = Flask(__name__)
Scss(app)
By default, the extension will look for your .scss files in {app.root_dir}/assets/scss
or {app.root_dir}/assets
and will put the generate .css files in {default_static_dir}/css
or {default_static_dir}
.
Libsass is a good solution for this.
# Your __init__.py file
from flask import Flask
from sassutils.wsgi import SassMiddleware
app = Flask(__name__)
app.wsgi_app = SassMiddleware(app.wsgi_app, {
myapp : ( static/sass , static/css , /static/css )
})
# Your HTML (Jinja) file
<link href="{{ url_for( static , filename= css/style.scss.css ) }}"
rel="stylesheet" type="text/css">
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