aaa.py:
import subprocess
print(11111)
exp = 0
subprocess.run([ python , bbb.py ])
print(22222)
print(exp)
bbb.py
import aaa
print("hello world")
print("bbb.py :", aaa.exp)
aaa.exp += 1
为什么它继续陷入 lo?
aaa.py:
import subprocess
print(11111)
exp = 0
subprocess.run([ python , bbb.py ])
print(22222)
print(exp)
bbb.py
import aaa
print("hello world")
print("bbb.py :", aaa.exp)
aaa.exp += 1
为什么它继续陷入 lo?
你们的履行使阿那.和贝.之间形成了一种循环依赖,导致一种无限的 lo。 让我们逐步结束所发生的事情:
1. aaa.py is executed.
2. import subprocess and print(11111) are executed.
3. exp is set to 0. subprocess.run([ python , bbb.py ]) runs bbb.py.
Now, in bbb.py:
4. import aaa tries to import aaa.py again.
这里的问题是:当香草进口甲时,它就在aa实施所有法典。 页: 1 由此形成了一种 lo,即甲草胺进口泡沫、乙.进口甲草胺和乙.,导致 lo。
How to fix this:
由于这两个方案都在获取和改变支出的价值,你可以把这个模块单独输入一个单元,并在阿阿那.py和b.py中进口。
expy
exp = 0
<>strong>aaaa.py
import subprocess
import exp
print(11111)
subprocess.run([ python , bbb.py ])
print(22222)
print(exp.exp)
bbb.py
import exp
print("hello world")
print("bbb.py :", exp.exp)
exp.exp += 1
<><>Output
11111
hello world
bbb.py : 0
22222
0
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