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上文提及的例外情况是:被扔进胎儿的情况如何?
原标题:What does above exception points to in exception info thrown?

The simplest built-in exception as below:

>>> 1/0
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
ZeroDivisionError: division by zero

整个报刊都例外。

Define function f1 and not to define myException:

def f1():
    try:
        print(1/0)
    except:
        raise myException( my exception )

Call f1():

>>> f1()
Traceback (most recent call last):
  File "<stdin>", line 3, in f1
ZeroDivisionError: division by zero

During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 5, in f1
NameError: name  myException  is not defined

当胎儿

Traceback (most recent call last):
  File "<stdin>", line 3, in f1
ZeroDivisionError: division by zero

thrown out,exception of print(1/0) is handled as we have seen that in the beginning.
Why the statement in the middle line is During handling of the above exception, another exception occurred: ,instead of After handling of the above exception, another exception occurred:?
What is above exception in the statement During handling of the above exception?It points to try ... except structure in f1 ,instead of exception resulted by 1/0?
If above exception points to exception resulted by 1/0,then After handling of the above exception, another exception occurred is better to describe all the exceptions here!

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