Question

因此,我不想再从实地重建我的方案。因此,在我这样做之前,我不会将10个不同的Tk()物体改变为顶级。我很想知道什么。我将着重从窗口1向2过渡,并再次回头。

from tkinter import *
Window1 = Tk()
Window2 = Tk()

Window1.title( first window )
Window1.geometry("800x800")

def Window_2():
   Window1.withdraw()
   Window2.title( Second Window )
   Window2.geometry("800x800")
   Button2.pack()
   Window2.mainloop()
....
....

Button1 = Button(Window1, text =  Go to 2 , command = Window_2)
Button2 = Button(Window2, text =  Go to 1 , command = lambda: [Window2.withdraw(), Window1.deiconify()])
Button1.pack()
Window1.mainloop()

我愿在窗户之间自由开一个封闭点和一个开放点。当我执政时,我可以坐到窗户2上,再回到1个罚款上,而窗口2只是下台的黑板。任何帮助都会受到高度赞赏。

Edit。如果你照此办理,我只说删除了两条。

Answer 1

您需要打电话<代码>Window2.deiconification(),而不是Window2.mainloop() 载于以显示hidden/em>Window2。

正如在评论中所说的那样,最好使用<代码>Toplevel()而不是儿童窗口,并且只需要使用mainloop()。

def Window_2(): Window1.withdraw() Window2.title( Second Window ) Window2.geometry("800x800") Button2.pack() Window2.deiconify() # for showing back Window2 if it is hidden # don t need to call mainloop() here

Also suggest to call Window2.withdraw() after creating Window2 to make it hidden initially.

Answer 2

下面是一部法典。你会看到,我正在就使用顶级提出建议。但我现在再次 st。

from tkinter import *

root = Tk()
root.title( change text )
Label1 = Label(root, text =  Change me )
Label1.pack()

def presto():
    Label1.configure(entry1.get())

def open_sub():
    top1 = Toplevel(root)
    top1.title( Buttons )
    label1 = Label(top1, text =  Type Something )
    entry1 = Entry(top1, width = 20)
    button1 = Button(top1, text = "execute", command = presto)
    button2 = Button(top1, text =  close , command = top1.destroy)
    label1.pack()
    entry1.pack()
    button1.pack()
    button2.pack()

button1 = Button(root, text =  page 2 , command = open_sub)
button1.pack()

root.mainloop()

因此,我知道此事无关,但确实对最初的问题作了回答。在试图改变标签时,存在新的问题。我发现错误代码:

Exception in Tkinter callback Traceback (most recent call last): File "/data/user/0/ru.iiec.pydroid3/files/aarch64-linux-android/lib/python3.11/tkinter/init.py", line 1948, in call return self.func(*args) ^^^^^^^^^^^^^^^^ File "/data/user/0/ru.iiec.pydroid3/files/temp_iiec_codefile.py", line 9, in presto Label1.configure(entry1.get()) ^^^^^^ NameError: name entry1 is not defined

而且,我可以把第1号从高级职能中删除,因为那时我才获得。

Traceback (most recent call last): File "/data/user/0/ru.iiec.pydroid3/files/temp_iiec_codefile.py", line 8, in entry1 = Entry(top1, width = 20) ^^^^ NameError: name top1 is not defined

我只字不提显示进展和可能赢得的不相关的问题。我不想删除原来的问题,因为这表明解决办法,而其他人可能认为它有用。

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