我刚刚读到Rope的文章,并且没有发现任何ope余额。 这是否意味着,任何带短str的双龙树都是一种ope?
How to implement a double linked list with only one pointer? It takes O(1) time to find the prev and next Node. struct Node { int val; Node* p; };
我刚刚读到Rope的文章,并且没有发现任何ope余额。 这是否意味着,任何带短str的双龙树都是一种ope?
这是否意味着,任何带短str的双龙树都是一种ope?
是的。 视执行情况,
通常,使用化肥的用途预计较少,因此,在努力实施平衡战略方面,以及(小型)管理成本方面,保持平衡战略的间接费用都没有价值。
The original rope paper does mention a rebalancing strategy which is based on Fibonacci numbers. "Ropes: an Alternative to Strings", by Boehm, Atkinson, and Plass, in SOFTWARE--PRACTICE AND EXPERIENCE, VOL. 25(12), 1315–1330 (DECEMBER 1995)
我同意,许多申请只使用几个节点,这意味着它们在不必担心重新平衡的情况下利用绳索。 但是,如果在图书馆里提供红树,那就必然需要保持树木平衡,因为它不知道申请要求。 See the BigList implementation in the PowerCollection Library from Wintellect for reference:
How to implement a double linked list with only one pointer? It takes O(1) time to find the prev and next Node. struct Node { int val; Node* p; };
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