Question

from django.contrib import admin
from django.urls import path
from . import views

urlpatterns = [
    path( admin/ , admin.site.urls),
    path("", views.home),
    path("predict/", views.predict),
    path("predict/result", views.result)

追溯

File "C:UsersuserPycharmProjectsDiabetes PredictionDiabetes_PredictionDiabetes_Predictionurls.py", line 19, in <module>
    from . import views
ImportError: attempted relative import with no known parent package

Answer 1

你们正在把项目层次的周期结合起来。页: 1 您的项目设计书载于载有您环境的名录。 py. 它希望:

from django.contrib import admin
from django.urls import path, include

urlpatterns = [
    path( admin/ , admin.site.urls),
    path(  , include( myapp.urls )),
]

页: 1 请各位在您的名录中,即你们有你们的看法和模式。在该名录中创建名为urls.py的档案。它希望:

from django.urls import path

from . import views

app_name =  myapp 
urlpatterns = [
    path(" ", views.home),
    path("predict/", views.predict),
    path("predict/result", views.result)

被占领土办事处没有在环境中书写名称。 py. 在环境中添加你的名字。页: 1

INSTALLED_APPS = [
    # Default apps
     django.contrib.admin ,
     django.contrib.auth ,
     django.contrib.contenttypes ,
     django.contrib.sessions ,
     django.contrib.messages ,
     django.contrib.staticfiles ,

    # My apps
     myapp ,     
]

www.un.org/Depts/DGACM/index_spanish.htm 请看一下,你似乎混淆了许多事情。另见《国际黄麻和黄麻制品公约》()。一个典型的Django项目由一个或多个附属公司组成。你利用“指挥编码”创建你的项目——项目名称<>django-admin>,并使用以下指挥编码(<代码>python管理)制作你的仪器。页: 1 请确保你不要把两者混在一起。还确保你在<条码>上填入“条码>。 See docs for more.

Answer 2

替换:

from django.contrib import admin
from django.urls import path
from your_appname import views # change here. 

urlpatterns = [
    path( admin/ , admin.site.urls),
    path("", views.home),
    path("predict/", views.predict),
    path("predict/result", views.result)

确保在您的环境下:

INSTALLED_APPS = [
    
    #others

    # internal app
     your_appname ,     
]

友情链接