联合王国的员额代码与B9 7RL一样。
I would like to keep the first block then the first letter of the second block like this BB9 7
我当时正在利用这一机会,但只给我像这本B9一样的首选。
preg_split( /[, ();.]/ , trim($string))[0]
联合王国的员额代码与B9 7RL一样。
I would like to keep the first block then the first letter of the second block like this BB9 7
我当时正在利用这一机会,但只给我像这本B9一样的首选。
preg_split( /[, ();.]/ , trim($string))[0]
如果你知道直截了当的形式,如果至少有两部分,你可以分开检查。
然后从阵列第二个项目中分离出第一个特性。
对于模式,如果您具有与特性类别所列内容相匹配的连续特性,则可以添加一个倍数的“<代码>+>,使你在由此而产生的一系列预言中留下空的物品。
$string = "BB9 7RL";
$result = preg_split( /[, ();.]+/ , trim($string));
$postalCode = $result[0];
if (count($result) > 1) {
$postalCode .= $result[1][0];
}
echo $postalCode;
产出
BB97
If you first want to validate the string for the postalcode first, you can refer to this page RegEx for matching UK Postcodes
您可以特别就你的情况尝试这一法典:
$postcode = "BB9 7RL";
$pattern = /^([A-Z]{1,2}[0-9][A-Z0-9]?)s*([0-9])[A-Z]{2}$/i ;
if (preg_match($pattern, $postcode, $matches)) {
$formatted = $matches[1] . . $matches[2];
echo $formatted; // Outputs: BB9 7
} else {
echo "Invalid postcode";
}
$postcode = "BB9 7RL";
$pattern = /([Gg][Ii][Rr] 0[Aa]{2})|((([A-Za-z][0-9]{1,2})|(([A-Za-z][A-Ha-hJ-Yj-y][0-9]{1,2})|(([A-Za-z][0-9][A-Za-z])|([A-Za-z][A-Ha-hJ-Yj-y][0-9][A-Za-z]?))))s?[0-9][A-Za-z]{2})/ ;
if (preg_match($pattern, $postcode, $matches)) {
$formatted = substr($matches[0], 0, strpos($matches[0], )) . . $matches[0][strpos($matches[0], ) + 1];
echo $formatted; // Outputs: BB9 7
} else {
echo "Invalid postcode";
}
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