我一直试图利用SciPy将2x dx从3到4,但正在退回一种不正确的价值。
from scipy.integrate import quad
def g(x):
return (2*(x**2))/2
quad(g,3,4)
回归的结果应为7个,但我结果为12.333个。
我一直试图利用SciPy将2x dx从3到4,但正在退回一种不正确的价值。
from scipy.integrate import quad
def g(x):
return (2*(x**2))/2
quad(g,3,4)
回归的结果应为7个,但我结果为12.333个。
您再次提供您打算整合的职能的证明,但scipy.integrate.quad(<>/code>期望这一职能本身。
换言之,如果你想要融合2*x,那么你应该提供2*x。
然而,由于你确实有抗争,你根本不需要<条码>。 你只能评估你在整体界限的开始和结束时的反弹。 当有机体没有已知的分析解决办法时,<代码>quad()的功能最为有用。
这方面的一个例子是,如何解决这一整体问题,没有<代码>quad()。
from scipy.integrate import quad
def g(x):
return 2 * x
def g_integral(x):
return (2 * (x**2))/2
print("Integral via numeric integration", quad(g, 3, 4))
print("Integral via analytic solution", g_integral(4) - g_integral(3))
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