EDITED LATER:

Question

取决于条件我想把一个纽子连接起来,与另一个功能连接起来。

我要说的是:

myButton = QtGui.QPushButton()

例如,我要说,如果存在互联网联系,我会检查。

if connected == True:
    myButton.clicked.connect(function_A)

elif connected == False:
    myButton.clicked.connect(function_B)

First of all I would like to disconnect a button from any function it was already connected before the button is being re-assigned/re-connected to another function (function_A or function_B). Secondly, I have already noticed that after the button is re-connected it takes an extra click for the button to pick up a new function. After the button is re-connected to another function it still attempts to run a previous function - a function to which a button was connected earlier (before a re-connection). Please advice. Thanks in advance!

EDITED LATER:

这种方法似乎是一种植被()。脱节()方法可用于将丁子与其相关的功能分离。

myButton.disconnect()

Unfortunately .disconnect() throws an error if a widget is not connected to any function. To get around it I am using Try/Except. But I would rather use a more elegant solution...

try: myButton.clicked.disconnect() 
except Exception: pass

Answer 1

如果你需要在许多地方重新连接信号,那么你可以确定一种通用的通用功能,如:

def reconnect(signal, newhandler=None, oldhandler=None):        
    try:
        if oldhandler is not None:
            while True:
                signal.disconnect(oldhandler)
        else:
            signal.disconnect()
    except TypeError:
        pass
    if newhandler is not None:
        signal.connect(newhandler)

...

if connected:
    reconnect(myButton.clicked, function_A)
else:
    reconnect(myButton.clicked, function_B)

(NB:由于可能已经连接了干燥的时间,因此有必要安全脱节,而<代码>脱节(位置)只取消了一段时间的一条连接。)

Answer 2

为此:

from PyQt4 import QtGui as gui

app = gui.QApplication([])

myButton = gui.QPushButton()

def function_A():
    myButton.clicked.disconnect() #this disconnect all!
    myButton.clicked.connect(function_B)
    print  function_A 

def function_B():
    myButton.clicked.disconnect(function_B) #this disconnect function_B
    myButton.clicked.connect(function_A)
    print  function_B 

myButton.clicked.connect(function_A)
myButton.setText("Click me!")
myButton.show()

app.exec_()

Answer 3

Concise way for 3.4+ with contextlib.suppress :

with contextlib.suppress(RuntimeError):
    button.clicked.disconnect()
button.connect(func_a if condition else func_b)

Answer 4

与此类似:

button.doubleClicked.connect(my_function)

它检查了纽特是否相互关联,如果是:

if button.doubledClicked.connect(my_function):
     button.doubledClicked.disconnect()

EDITED LATER:

友情链接