Question

在java,我们利用半殖民地,根据半殖民者的理解,发言结束。

中文不适用。用途 JRV 编辑们如何理解这一点,是在<条码>Kotlin上没有半分辨率的结束发言?

Answer 1

如here。

In Kotlin, semicolons are optional, and therefore line breaks are significant.

this essentially means kotlinc can identify the end of a statment in same manner as javac does, only difference is the character that marks the end of statement, where javac looks for ;, kotlinc would look for a (line break).

Please note that use of semicolon is required when declaring an enum class in kotlin.

for example following code will not compile if you omit the semicolon

enum class Fruit(val price: Double) {
    MANGO(100.0);

    fun printPrice(){
        print(price)
    }
}

Answer 2

<> 补充答复>

Kotlin lexer parser在通过TruncedSemantic WhiteA

This line break recognition is done without having to insert (or replace them with semicolons). Check the discussion here
Semantic WhitespaceAwarePBsiuiperImplp/<> https://github.com/JetBrains/kotlin/blob 2. 如何开展工作的方法:

@Override
public boolean newlineBeforeCurrentToken() {
    if (!newlinesEnabled.peek()) return false;

    if (eof()) return true;

    // TODO: maybe, memoize this somehow?
    for (int i = 1; i <= getCurrentOffset(); i++) {
        IElementType previousToken = rawLookup(-i);

        if (previousToken == KtTokens.BLOCK_COMMENT
                || previousToken == KtTokens.DOC_COMMENT
                || previousToken == KtTokens.EOL_COMMENT
                || previousToken == SHEBANG_COMMENT) {
            continue;
        }

        if (previousToken != TokenType.WHITE_SPACE) {
            break;
        }

        int previousTokenStart = rawTokenTypeStart(-i);
        int previousTokenEnd = rawTokenTypeStart(-i + 1);

        assert previousTokenStart >= 0;
        assert previousTokenEnd < getOriginalText().length();

        for (int j = previousTokenStart; j < previousTokenEnd; j++) {
            if (getOriginalText().charAt(j) ==  
 ) {
                return true;
            }
        }
    }

    return false;
}

每当需要检查象征性的:
private boolean tokenMatches(IElementType token, IElementType expectation) {
    if (token == expectation) return true;
    if (expectation == EOL_OR_SEMICOLON) {
        if (eof()) return true;
        if (token == SEMICOLON) return true;
        if (myBuilder.newlineBeforeCurrentToken()) return true;
    }
    return false;
}

因此,newlineBeforeCurrent Token() parses nature by nature and compars nature and compars it to a linebreak,并最终表示其发言内容完整。

Answer 3

Semicolons add no human-valuable meaning to the code. Life’s too short to bother with them. This is only one (admittedly minor) of many examples of non-essential complexity in Java that is removed by more modern JVM languages.

Answer 4


In Kotlin, Semicolons are optional, but line breaks are significant.

Kotlin汇编者通常承认发言结束,即使没有明确的<代码>;,例如通过细线休息。

<>Important: 如果您想用一条单行发言,则与<条码>分开。

例:

    val a = 42 ; println(a)

Please note that use of semicolon is required when declaring an enum class in kotlin.

友情链接