Question

在Xml文档中,我正在寻找“和带;档案:write”和xml文档有一个完整的Xml标签,在标签中,它具有价值。我正试图用档案名称对Csv档案中提交的价值进行计算。问题在于,实地(街区和路道)是第2、第3或第4栏,我无法使用截断指挥部。

是否有更好的办法这样做?

find /opt/mortagage/application.xml -type f -exec egrep -ri "<file:write" /dev/null {} + |uniq| sed  /<!--.*-->/d  | sed  /<!--/,/-->/d 

/opt/mortagage/application.xml:              <file:write doc:id="16630" path="${file.location}" doc:name="Save file to directory">
/opt/mortagage/application.xml:                      <file:write doc:name="Write to complete folder" doc:id="18890" path= #["${file.completeLocation}" ++ vars.zipFileName]  config-ref="File_Config_completed">
/opt/mortagage/application.xml:                      <file:write doc:name="Write to complete folder" doc:id="19990" Path= #["${file.completeLocation}" ++ vars.zipFileName]  config-ref="File_Config_completed">

Answer 1

一种“更好的方式”是使用专用处理器进行结构化的数据,在这种情况下,指挥线XML处理器可以很容易地这样做。

Using kislyuk/yq:

xq -r  .. | ."file:write"? | arrays[] // . | ."@path", ."@Path" | strings  in.xml

Using mikefarah/yq (完全无视名称空间):

yq -oy  .. | .write? | select(kind == "map") // .[] | ."+@path" // ."+@Path"  in.xml

使用 xmlstarlet:

xmlstarlet sel -t -m  //file:write  -v  @path  -v  @Path  -n in.xml

使用libxml/xmllint:

xmllint requires to either declare the actual namespaces (which you haven t provided in the sample), or to defect to ignoring them all by resorting to a local-name() check
xmllint also doesn t support the string(…) function on multiple matches, so the best it can do is to output full attribute nodes like path="${file.location}". A workaround could be to subsequently use another tool (like awk or sed) to trim them down.

xmllint --xpath  //*[local-name()="write"]/@path | //*[local-name()="write"]/@Path  in.xml |
  sed  s/^.*?="|"$//g  # removes all up to the first =" and a final "

All of them output something like:

${file.location}
#["${file.completeLocation}" ++ vars.zipFileName]
#["${file.completeLocation}" ++ vars.zipFileName]

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