Question

My DataGridView displays information that is entered on another system. As the user insert, update or delete any information, the DataGridView should be updated right now.
I thought about using a recursive method or thread background, but it did not help.
My code is:

private void Andon_Load(object sender, EventArgs e)
{
    LoadGrid();
}

private void LoadGrid()
{
    DataTableWorkCall cdtwc = new DataTableWorkCall();
    DataTable dtPBList = new DataTable();

    dtPBList = cdtwc.CreatePendingWorkCall();
    DataTableWorkCall.GetDataTableNew = dtPBList;


    if (DataTableWorkCall.GetDataTableNew != DataTableWorkCall.GetDataTableOld)
    {
        if (DataTableWorkCall.GetDataTableNew.Rows.Count > 0)
        {
            DataTableWorkCall.GetDataTableOld = DataTableWorkCall.GetDataTableNew;
            if (this.WindowState == FormWindowState.Minimized)
                this.WindowState = FormWindowState.Normal;
            DataView dv = new DataView(DataTableWorkCall.GetDataTableNew);
            dv.Sort = "workCallOpenDate DESC";
            dgvAndon.DataSource = dv;
            lblRefreshDate.Text = "Atualizado em: " + DateTime.Now;
            existData = true;
        }
        else
        {
            if (this.WindowState == FormWindowState.Normal)
                this.WindowState = FormWindowState.Minimized;

            music.Clear();
            music.StopSound();

            lblRefreshDate.Text = "Atualizado em: " + DateTime.Now;
            existData = false;
        }

        this.Activate();
        //LoadGrid();
    }
    else
    {
        if (this.WindowState == FormWindowState.Normal)
            this.WindowState = FormWindowState.Minimized;

        lblRefreshDate.Text = "Atualizado em: " + DateTime.Now;
        existData = false;

        LoadGrid();
    }

}

这不能奏效,谁能帮助我?

Answer 1

这样做的最简单方式(如Sshahid Iqbal所说)是在规定的时间间隔内使用一个时间,并将你的数据网格对数据来源进行重新设计,但用户可能不会改变相关的数据来源。

但是,如果你想采取更强有力的办法,则采取下列行动:

实时 DataGridView?

你们看到,履行这一职能需要一些时间。

友情链接