Question

这是我迄今为止的职能守则(如果出现错误的话):

def showAddition():
    print("You have selected: "Addition"")
            
    while True:
        last_answer = None
        if last_answer:
            next_num = int(input("Please input another number: "))
            answer = calc.addNums(last_answer, next_num)
        else:
            num1 = int(input("Please enter your first number: "))
            num2 = int(input("Please enter your second number: "))
            answer = calc.addNums(num1, num2)
                
            print(f Your answer is {answer} )
            continue_prompt = input("Would you like to continue? Y/N
")
                    
            if continue_prompt.upper() == "Y" or continue_prompt.upper() == "YES":
                last_answer = answer
            else:
                break

我正试图这样做,以便我能够立即进入另一个编号,在数字后增加数字,而不会失败。然而,出于某种原因,这 lo只是重复。即便我对“不”的继续迅速投入,它甚至没有中断。 “赞成”和“反对”都产生了完全相同的结果,而没有结果。

Answer 1

def showAddition():
    print("You have selected: "Addition"")
    
    # store the result of the previous addition
    last_answer = None
    # to stop the loop
    continue_adding = True
    
    while continue_adding:
        if last_answer:
            next_num = int(input("Please input another number: "))
            # answer = last_answer + next_num
            answer = calc.addNums(last_answer, next_num)
            print(f Your answer is {answer} )
            # store new value in last answer
            last_answer = answer
        else:
            num1 = int(input("Please enter your first number: "))
            num2 = int(input("Please enter your second number: "))
            # answer = num1 + num2 
            answer = calc.addNums(num1, num2)
                
            print(f Your answer is {answer} )
            
            # check input
            while True:
                continue_prompt = input("Would you like to continue? Y/N
")
                # continue addition directly with stored last_answer
                if continue_prompt.upper() in {"Y","YES"}:
                    last_answer = answer
                    break
                elif continue_prompt.upper() in {"N","NO"}:
                    # stop the loop
                    continue_adding = False
                    break
                else:
                    # ask again to only input Y/N
                    print("Only Enter Either Y/N")
                    continue

store the last answer into the variable above while loop so it won t reset
set loop variable continue_loop used to stop while loop without over coding the inputs if it s not Y/N
Instead of using if x == y use set or list look ups: if x in [x,y,z]

Answer 2

除了Razumov关于纠正这一缺陷的建议外,注意到“投入另一号”组将永远不会运行,因为last_answer<>code>在每次停机时都会被重新定位为零。只字不提......


如果你打算报告整整整整整整整整段的累积数额,就会尝试:
class calc:
    @staticmethod
    def addNums(*args):
        return sum(args)


def showAddition():
    print("You have selected: "Addition"")

    last_answer = None
    while True:
        if last_answer:
                        next_num = int(input("Please input another number: "))
            answer = calc.addNums(last_answer, next_num)
        else:
            num1 = int(input("Please enter your first number: "))
            num2 = int(input("Please enter your second number: "))
            answer = calc.addNums(num1, num2)

        print(f Your answer is {answer} )
        continue_prompt = input("Would you like to continue? Y/N
")

        if continue_prompt.upper() == "Y" or continue_prompt.upper() == "YES":
            last_answer = answer
        else:
            break

(You没有提供calc.addNums的实施,我补充说,在执行过程中,我可以操作该守则。)

Answer 3

你们是否尝试使用 b变,而不是打破2级?

i.e.

def showAddition():
    print("You have selected: "Addition"")
        
    continueProcess = True    
    while continueProcess:
        last_answer = None
        if last_answer:
            next_num = int(input("Please input another number: "))
            answer = calc.addNums(last_answer, next_num)
        else:
            num1 = int(input("Please enter your first number: "))
            num2 = int(input("Please enter your second number: "))
            answer = calc.addNums(num1, num2)
                
            print(f Your answer is {answer} )
            continue_prompt = input("Would you like to continue? Y/N
")
                    
            if continue_prompt.upper() == "Y" or continue_prompt.upper() == "YES":
                last_answer = answer
            else:
                continueProcess = False

友情链接