Question

我的描述很新。我正试图写一个文字,以检查错误的日志(手法硬编码),我必须印刷含有错误的文字。 i 能够书写逻辑,但需要点人阅读用户投入文件。

Appreciate the help thanks.

Logic:

Accept the logfile patch from user
Check if the logfile is present or not
If present search the file for lines containing the error string (eg. Error, ORA)
Print the lines containing error strings , also write the output to a logfile

阅读用户的日志

3. 错误指示

search="ERROR"

set a path for output file

outfile="file1.txt"

Execution logic

find "$mydir" -type f -name "$filename" |while read file
  do
    RESULT=$(grep "$search" "$file")
      if [[ ! -z $RESULT ]]
         then
            echo "Error(s) in $file: $RESULT" >> "$outfile"
     fi
  done

Answer 1

我不肯定你所说的“用点人读用用户投入的文件”。我假定“点人”是文字论据。

您可以使用这一文字:

#!/bin/bash
expected=outfile
for f in $@
do
  if [ "$expected" = outfile ]; then
      OUTFILE=$1
      expected=search
  elif [ "$expected" = search ]; then
      SEARCH=$2
      expected=files
  elif [[ -f $f ]]; then
      RESULT=`grep "$SEARCH" $f`
      if [ -n "$RESULT" ]; then
           echo -e "
"
           echo "Error(s) in "$f":"
           echo $RESULT
           echo -e "
" >> $OUTFILE
           echo "Error(s) in "$f":" >> $OUTFILE
           echo $RESULT >> $OUTFILE
      fi
  fi
done

Invoke with:

scriptname outfile search files

:

scriptname: is the name of file containing the script.
outfile: the name of the output file
search: the text to be searched
files: one or many file name or file patterns.

例子(我假定文字名称是搜索器,正处在系统轨道):

searcherror errorsfound.txt primary /var/log/*.log

searcherror moreerrors.txt "ORA-06502" file1.log /var/log/*.log ./mylogs/*

Logic:

Execution logic

友情链接