Question

我有一个图表清单:

x = [( router_1 ,  0/1 ,  0/4 ,  router_2 ),
     ( router_1 ,  0/2 ,  0/4 ,  router_3 ),
     ( router_4 ,  0/1 ,  0/5 ,  router_5 ),
     ( router_4 ,  0/2 ,  0/5 ,  router_6 )]

目标是构建以下数据:

dict = {"details": [
        {
            "router_1": {
                "connections": [
                    {
                        "side_a": {
                            "device": "router_1",
                            "interface": "0/47",
                        },
                        "side_b": {
                            "interface": "0/17",
                            "device": "router_2",

                        }
                    },
                    {
                        "side_a": {
                            "device": "router_1",
                            "interface": "0/48",
                        },
                        "side_b": {
                            "interface": "0/17",
                            "device": "router_3",
                        }
                    }
                ]
            }
        },
        {
            "router_4": {
                "connections": [
                    {
                        "side_a": {
                            "device": "router_4",
                            "interface": "0/47",
                        },
                        "side_b": {
                            "interface": "0/17",
                            "device": "router_5",
                        }
                    },
                    {
                        "side_a": {
                            "device": "router_4",
                            "interface": "0/48",
                        },
                        "side_b": {
                            "interface": "0/17",
                            "device": "router_6",
                        }
                    }
                ]
            }
        }
    ]
}

请注意:

the key router_1 created based on the device name under "side_a"
the key router_4 created based on the device name under "side_a"

I tried below :

import collections
data_dict = collections.defaultdict(list)

result = {}

for item in x:
 router_a, router_a_int, router_b_int, router_b = item
 result[side_a] = data_dict["connections"].append({"side_a": {
 "hostname": router_a,
 "interface": router_a_int},
 "side_b": {
 "interface": router_b_int,
 "hostname": router_b
 }})

然而, 字典的价值正在显示“None”。象每个时间的 app一样,使价值变得无所作为,但我通过收集信息来消除这一问题。

请您提供帮助。

谢谢。

Answer 1

你只是需要调整你如何在 lo体内建立字典结构。

引证:

from collections import defaultdict

data_dict = defaultdict(list)

for item in x:
    router_a, router_a_int, router_b_int, router_b = item
    data_dict[router_a].append({
        "side_a": {
            "device": router_a,
            "interface": router_a_int
        },
    "side_b": {
        "interface": router_b_int,
        "device": router_b
    }
})

result = {"details": [{"{}".format(router): {"connections": connections}} for router, connections in data_dict.items()]}
print(result)

I tried below :

友情链接